A particle moves on the curve
-, where x=t/2.
x and y are measured in metre and t in second. At
t = 4 s, the velocity of particle is
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Explanation:
Bonjour
↪Actually welcome to the concept of the CALCULUS APPROACH AS KINEMATICS
↪Basically here we are given the equation of the curve ( trajectory of the particle )
↪It is given as ,
↪Y = x^2/4 , Also , X is the parameter of time as , X = t/2
↪Now we know that ,
↪Velocity is given as , If y = displacement and t is time
↪the Velocity = dy/dt
↪thus solving and substituting the value of curve we get as ,
↪dy/dt = 2x/ 4 = X /2 m/s
↪also here , we know that , x = t/2 , so
↪V = t/4 , velocity at , t=4 will be as
〽V = 4/4 = 1 m/s
⭐so velocity at t=4 is 1 m/s
Hope helps uh❤️❤️
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