Question

a particle moves on the curve y=x^2/4, where x=t/2. x and y are measured in meter and t in second. At t=4 s, the velocity of particle is

Answer 1

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually welcome to the concept of the CALCULUS APPROACH AS KINEMATICS

↪Basically here we are given the equation of the curve ( trajectory of the particle )

↪It is given as ,

↪Y = x^2/4 , Also , X is the parameter of time as , X = t/2

↪Now we know that ,

↪Velocity is given as , If y = displacement and t is time

↪the Velocity = dy/dt

↪thus solving and substituting the value of curve we get as ,

↪dy/dt = 2x/ 4 = X /2 m/s

↪also here , we know that , x = t/2 , so

↪V = t/4 , velocity at , t=4 will be as

〽V = 4/4 = 1 m/s

⭐so velocity at t=4 is 1 m/s

Answer 2

Answer:

Explanation:answer is √2 m/s