Physics, asked by rudrakshtatwal24, 1 month ago

A particle moves on x-axis as per equation x = (t3 – 9t2 + 15 t + 2)m. Distance travelled by the particle between t = 0 and t = 5 s is (A) 25 m (B) 39 m (C) 23 m (D) 52 m

Answers

Answered by Muskansolanki555
2

Explanation:

particle moves on x-axis as per equation x = (t3 – 9t2 + 15 t + 2)m. Distance travelled by the particle between t = 0 and t = 5 s is (A) 25 m (B) 39 m (C) 23 m (D) 52 m

answer is 25 m

Answered by vrindaa27
1

Answer:

25m

Explanation:

at t=5s

x =  {5}^{3}  - 9 \times  {5}^{2}  + 15 \times 5 + 2 =  - 23

at t=0s

x=2m

therefore distance =23+2=25m

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