Question

A particle moves over 3/ quarters of a circle of radius r what is the magnitude of its displacement?

Answer 1

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Answer 2

A particle moves over three quarters of a circle of radius r. What is the magnitude of its  displacement?

Radius of circle =r

Body moves over 3 quarters

Magnitude of displacement = the hypotenuse of the 4th quarter whose Base and perpendicular r both = r unit.

Then,

(Hypotenuse)² = base² +perpendicular²

H² =r² +r²

H^2=2r²  

H=√2r²

The magnitude of its displacement √2r²