A particle moves over one quarter of a circle of radius r. What is the magnitude of its
displacement?
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Answer:Given particle covers three quarters of a circle with radius R.
Distance travelled = 3/4(circumference of circle)
=3/4(2*pi* r)
= 3/2 ( pi* r).
DISPLACEMENT=SHORTEST PATH
= IF WE JOIN POINT A and B we get right angle triangle with
Hypotenuse(displacement) and other two sides of triangle with sides r.
Displacement =Sqr(r^2 +r^2)
=sqr(2r^2)
=r*sqr(2)
=1.41*r meters
Therefore Displacement covered by particle is 1.414*r m
Explanation:
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