Question

A particle moves over three quarters of a circle of radius r. What is the magnitude of it's displacement?​

Answer 1

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\purple{Answer:-}$

⏩ When the particle covers three quarters of a circle, the magnitude of it's displacement is:-

$</em><em>AB</em><em> = \sqrt{</em><em>OA</em><em>^{2} + </em><em>OB</em><em>^{2} }$

$= \sqrt{r^{2} + r^{2} }$

$= \sqrt{2r}$

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Hope it helps...:-)

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