Question

A particle moves such that its acceleration ‘a’ is given by a
= – bx where x is the displacement from equilibrium position
and b is constant. The period of oscillation is
(a) 2 π/b (b) 2π/ √b
(c) √2 π / b (d) 2 √π / b

Answer 1

Answer:

ANSWER

a=−ω

2

x=−bx

Thus, ω=

b

Thus, T=

ω

2π

=

b

2π