Question

A particle moves through a distance of 3 m due east and then 4 m due north.
(a) How much is the net distance traversed ?
(b) What is the magnitude of the net displacement ?
its numerical of physics of class 9th​

Answer 1

Answer:

Explanation:

write the given data

first a particle moves 3m north

which means in paper 3m right wards and a particle moves 4m north

and which means 4m upwards from the respective position

join the starting point of particle and ending point of particle by diagonal

now it is triangle

find hypopotenuse which is net displacement