Question

A particle moves through a distance of 3 m due east and then 4 m due north.
(a) How much is the net distance traversed ?
(b) What is the magnitude of the net displacement ?​

Answer 1

Answer:distance ==7m and displacement===√3^2+4^2

5m

Explanation:

Answer 2

Ans:

Distance=7m and displacement=5m

Explanation:

Total distance=3m+4m

                       =7m

Displacement=3square + 4square

                      =9+16

                      =root of 25

                      =5m