a particle moves through a distance of 3m distance of 3m due east and then 4m due north. how much is the net distance and displacement
Answers
Answer :
Distance travelled is 7m and displacement is 5m.
Given Information :
- A particle moves through a distance of 3m due east and then 4m due north.
To calculate :
- Net distance and displacement
Clarification :
In order to tackle this question, we need to understand what is meant by distance and displacement.
Distance is the length of the total path covered by the body. Its SI unit is m (metre) and it is a scalar quantity which means that it requires onlu magnitude for its description.
Displacement is the shortest distance from the body's initial and the final position. Its SI unit is m (metre) and it is a scalar quantity which means that it doesn't require both magnitude and direction for its description.
Explication of steps :
In this question, it is stated that the particles firstly moves 3m in East and then 4m in North. So,
→ Distance travelled = 3m + 4m
→ Distance travelled = 7 m
Therefore , distance travelled by the particle is 7m.
Now, we have to calculate displacement. Since, we know that displacement is the shortest distance from the body's initial and the final position. The shortest distance from initial to final position is always a straight line. So, by using the Pythagoras property,
→ (Displacement)² = (3m)² + (4m)²
→ (Displacement)² = 9m² + 16m²
→ (Displacement)² = 25m²
→ Displacement = √(25m²)
→ Displacement = 5m
Therefore, displacement of the particle is 5m.
Answer:
Distance = 7m and Displacement = 5m
Explanation: