Question

A particle moves through a distance of 8 m due East and then 6 m due North. Then the magnitude of Displacement is

a) 2 m
b) 14 m
c) 6 m
d) 10 m​

Answer 1

Answer:

Correct option is d- 10

Explanation:

Answer. Since displacement is the shortest path travelled by the body then we have to find AC. So, the displacement of the particle is 10 cm .

Answer 2

Answer:

d

Explanation:

According to the question,,

BC = 6cm

AB = 8cm

To find : displacement of particle

Since displacement is the shortest path travelled by the body then we have to find AC.

AC^2 = AB^2 + BC^2 ( by pythagoras therom)

AC^2 = 8^2 + 6^2

AC^2 = 64 + 36

AC^2 = 100

AC = root 100

AC = 10cm

So, the displacement of the particle is 10 cm .