A particle moves through a distance of 8 m due east and then 6M due north then the magnitude of displacement is
Answers
Answered by
4
Given:
In ΔABC according to question
BC= 6m
AB= 8m
Find displacement of particle
displacement is a shortest path travelled by the body find AC
In ΔABC
AC²=AB² + BC²
AC²=8² + 6²
AC²=64+36
AC²=100
AC=10
Hence the magnitude of displacement is 10m
Answered by
1
Given:
According to the question, in ABC
6 m BC
8m AB=
To Find:
Determine the particle's displacement.
The shortest path taken by the body to find AC is called displacement.
ABC is an abbreviation for alphabetical order.
AC²=AB² + BC²
AC²=8² + 6²
AC²=64+36
AC²=100
AC=10
As a result, the displacement is 10 meters.
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