Question

a particle moves through a distance of 8 m due east and then 6 m due north .then the magnitude of the displacement is ?

Answer 1

According to the question,,

BC = 6cm

AB = 8cm

To find : displacement of particle

Since displacement is the shortest path travelled by the body then we have to find AC.

AC^2 = AB^2 + BC^2 ( by pythagoras therom)

AC^2 = 8^2 + 6^2

AC^2 = 64 + 36

AC^2 = 100

AC = root 100

AC = 10cm

So, the displacement of the particle is 10 cm .

Answer 2

Answer:

There is a formula AB^2+BA^2

then 8^2 + 6^2 is 100

then root 100 is 10