Question

A particle moves through angular displacement theta(ยฐ) on a circular path of radius r .the linear displacement will be

Answer 1

Given data states the angular displacement $\theta$ with radius as r. Therefore for the angular displacement, it is a multiplication of the angle and the radius and for the linear displacement, the displacement is turned into sine form.

Therefore, the given data infers the linear displacement to be $\frac { sin\theta }{ linear\quad displacement } =\frac { sin(\pi-2\theta ) }{ r } \Rightarrow linear\quad displacement=\frac { sin\theta }{ \frac { sin(\pi-2\theta ) }{ r } } .$