Question

a particle moves towards east from A to B at the rate of 4km/hr and then towards north from B to C at the rate of 5km/hr. Finally it reaches A. If AB=12km and BC=10km.Find the average velocity of the particle for the whole journey.​

Answer 1

Answer:

Average velocity of the particle for the whole journey=7.078

Answer 2

Answer:

The average velocity of the particle for whole journey is 0.

Explanation:

Given that,

A particle moves towards east from A to B at the rate of 4 km/hr and then towards north from B to C at the rate of 5 km/hr.

Distance of AB = 12 km

Distance of BC = 10 km

We need to calculate the time ,

The time is equal to the distance divided by the velocity.

Time to covered the distance A to B is ,

$t =\dfrac{d}{v}$

$t=\dfrac{12}{4}$

$t =3\ s$

Time to covered the distance B to C is ,

$t=\dfrac{10}{5}$

$t =2\ s$

The total time is 5 sec.

The distance AC is

Using Pythagorean theorem,

$AC=\sqrt{(12)^2+(10)^2}$

$AC=15.62\ km$

A particle starts from point A and finally reach at point A then the displacement is zero.

The average velocity is defined as,

$v_{avg}=\dfrac{D}{T}$

Where, D = Displacement

T = Total time

$v_{avg}=\dfrac{0}{2+3}$

$v_{avg}=0\ km/s$

Hence, The average velocity of the particle for whole journey is 0.