Physics, asked by ankitssm5970, 1 year ago

A particle moves uniformly in a circle of radius 10cm, covering a linear distance of 5cm in a time of 2.5seconds Find the time taken for 10 revolutions

Answers

Answered by fudailayham
9

Time(t) taken for travelling 10 cm is 2.5 sec.

So speed=distance/time

=> s=0.05m/2.5sec

=>0.02m/s

Now for travelling 10 revolution=10cm×10rev

=100cm=1m

Again s=d/t

=>0.02=1/t

=>t=1/0.02

=50sec

Time taken for 10 rev is 50sec

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Answered by pnuaponnuru
0

Answer:

314 s

Explanation:

v = 5/2.5 = 2 cm/s

Angular velocity = v/r = 2/10 = 1/5 rad/s Angular velocity = 2πn/t 1/5 =2πx10/t solving for time we get 100π = 100x3.14 =314 s

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