A particle moves uniformly in a circle of radius 25cm at two revolution per second. Find the acceleration of the particle in m/s^2
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First up,SI unit of acceleration is (m)/(s^2);
Radius=25 cm;
Rotations per second or Angular Velocity=2 rotations/second;
Which is ( 720°/second) or
(4 πradians/second);
Now ,acceleration in m/s^2 units, is linear acceleration, right?
So what we need to do is find out acceleration with the help of angular displacement per second and radius.
=> acceleration
=(( Angular velocity)^2)× Radius
=> acceleration= ((4π)^2) ×(25) cm/sec^2
=>acceleration= 3947.84176 cm/sec^2
Or 39.4784176 m/sec^2
Since the question has lesser significant digits the answer is 39.48 m/sec^2.
hope it helps you
plz mark it as a brainliest answer
Radius=25 cm;
Rotations per second or Angular Velocity=2 rotations/second;
Which is ( 720°/second) or
(4 πradians/second);
Now ,acceleration in m/s^2 units, is linear acceleration, right?
So what we need to do is find out acceleration with the help of angular displacement per second and radius.
=> acceleration
=(( Angular velocity)^2)× Radius
=> acceleration= ((4π)^2) ×(25) cm/sec^2
=>acceleration= 3947.84176 cm/sec^2
Or 39.4784176 m/sec^2
Since the question has lesser significant digits the answer is 39.48 m/sec^2.
hope it helps you
plz mark it as a brainliest answer
Answered by
0
Answer:
4 pi^2
Explanation:
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