Question

A particle moves with a speed of V1 for half of the distance in the remaining it moves with V2 for the half the time and with V3 for the next half two time find the average speed of value is​

Answer 1

Answer:

Average Velocity =  2V1(V2 + V3)/ (V1 + V2 + V3)

Explanation:

Let say Total Distance = 2D

Half Of  Distance = 2D/2 = D

Time Taken = D/V1

Remaining Distance = 2D - D = D

Let say time taken for this Distance = 2T

D = V2T + V3T

=> T = D/(V2 + V3)

Total Time  = D/V1  + D/(V2 + V3)  =( D/V1(V2 + V3)) (V1 + V2 + V3)

= D(V1 + V2 + V3)/V1(V2 + V3)

Total Distance = 2D

Average Velocity = 2D / (D(V1 + V2 + V3)/V1(V2 + V3))

= 2V1(V2 + V3)/ (V1 + V2 + V3)