A particle moves with a uniform speed of 2 m/s in x-
y plane according to the equation y= 4x, where x and
yare in metre. The acceleration of the particle along y
axis while passing through the origin has magnitude
Answers
Answered by
0
Step-by-step explanation:
Given,
x=4t
2
+5t+16
y=5t
velocity along x-axis
v
x
=
dt
dx
=(8t+5)m/s
acceleration along x-axis,
a
x
=
dt
v
x
=8m/s
velocity alon y-axis
v
y
=
dt
dy
=5m/s
acceleration along y- axis,
a
y
=
dt
v
y
=0m/s
The acceleration of the particle is given by
a
=a
x
i
^
+a
y
j
^
∣
a
∣=
a
x
2
+a
y
2
a=
8
2
+0
2
=8m/s
2
The correct option is A.
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