Question

A particle moves with a velocity v = 2t along a straight line
The average speed in time interval t=0 to t = 3s is​

Answer 1

Answer:

Explanation:

Average velocity =  

Δt

s

​

=v  

avg

​

 

S=∫  

0

5

​

vdt=∫  

0

5

​

(4t−t  

2

)dt=  

3

25

​

m

v  

avg

​

=  

5sec

25/3m

​

=  

3

5

​

 

sec

m

​

 

Average speed =  

time taken

distance covered

​

=  

Δt

distance

​

 

Distance =∫  

0

4

​

vdt+∫  

4

5

​

(−v)dt=  

3

32

​

+  

3

7

​

=  

3

39

​

m=13m

Average speed =  

5sec

13m

​

 

Average acceleration (a  

avg

​

)=  

Δt

v  

f

​

−v  

i

​

 

​

 

v  

f

​

=4×5−5  

2

=20−25=−5

v  

i

​

=0

a  

avg

​

=  

5

−5−0

​

=−1m/s  

2