Question

A particle moves with a velocity v  = (5 i ˆ – 3 j ˆ + 6 k ˆ ) m/s under the influence of a constant force F  = (10 i ˆ + 10 j ˆ + 20 k ˆ )N. The instantaneous power applied to the particle is :

Answer 1

Answer:

Explanation:

VELOCITY VECTOR=5 i^-3 j^+6 k^

FORCE = 10 i^+ 10 j^ + 20 k^

POWER APPLIED =?

POWER= DOT PRODUCT OF FORCE AND VELOCITY

POWER= F.V

POWER=5 i^*10 i^+ (-3 j^*10 j^)+6 k^* 20 k^

NOTE: i^*i^=1

           j^*j^=1

           k^*k^=1

POWER=5*10+-3*10+6*20

POWER=50-30+120

POWER=140 NM.

HOPE IT HELPS.