Question

a particle moves with a velocity v=5i-3j+6k m/s- under the influence of a constant force F=10i+10j+20k N .The instantaneous power applied to the particle is. a)200j-s– b)40 j-s– c)140j-s– d)170j-s–​

Answer 1

Answer:

Option (c)140J-s

power(P)=F.v

=(10i+10j+20k).(5i-3j+6k)

=10*5-10*3+6*20=50-30+120=140j-s

Answer 2

The instantaneous power applied to the particle is 140 J-s.

Explanation:

Given that,

Velocity of the particle, $v=(5i-3j+6k)\ m/s$

Force acting on the particle, $F=(10i+10j+20k)\ N$

We know that the relation between power, velocity and the force is given by :

$P=F{\cdot}v\\\\P=(10i+10j+20k){\cdot} ({5i-3j+6k})$

Now using dot product properties we get :

$P=50-30+120\\\\P=140\ J-s$

So, the instantaneous power applied to the particle is 140 J-s. Hence, this is the required solution.

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