a particle moves with a velocity v=5i-3j+6k m/s- under the influence of a constant force F=10i+10j+20k N .The instantaneous power applied to the particle is. a)200j-s– b)40 j-s– c)140j-s– d)170j-s–
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Answered by
12
Answer:
Option (c)140J-s
power(P)=F.v
=(10i+10j+20k).(5i-3j+6k)
=10*5-10*3+6*20=50-30+120=140j-s
Answered by
6
The instantaneous power applied to the particle is 140 J-s.
Explanation:
Given that,
Velocity of the particle,
Force acting on the particle,
We know that the relation between power, velocity and the force is given by :
Now using dot product properties we get :
So, the instantaneous power applied to the particle is 140 J-s. Hence, this is the required solution.
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