A particle moves with an acceleration of 2metrtpersec square. distance travelled by body in 5th half sec
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fifth half second = 2s - 2.5s
ti = initial time = 2 s
tf = final time = 2.5 s
vi = initial velocity = ti * a = 2s * 2m/s/s = 4m/s
vf = final velocity = tf * a = 2.5s * 2m/s/s = 5m/s
vf^2 - vi^2 = 2ax
(vf^2 - vi^2)/(2a) = x
(25 - 16)/4 = x
x = 9/4
x = 2.25 m........
I think it is ur answer
ti = initial time = 2 s
tf = final time = 2.5 s
vi = initial velocity = ti * a = 2s * 2m/s/s = 4m/s
vf = final velocity = tf * a = 2.5s * 2m/s/s = 5m/s
vf^2 - vi^2 = 2ax
(vf^2 - vi^2)/(2a) = x
(25 - 16)/4 = x
x = 9/4
x = 2.25 m........
I think it is ur answer
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