Question

A particle moves with an acceleration of 2metrtpersec square. distance travelled by body in 5th half sec

Answer 1

fifth half second = 2s - 2.5s  
ti = initial time = 2 s  
tf = final time = 2.5 s  
vi = initial velocity = ti * a = 2s * 2m/s/s = 4m/s  
vf = final velocity = tf * a = 2.5s * 2m/s/s = 5m/s  

vf^2 - vi^2 = 2ax  
(vf^2 - vi^2)/(2a) = x  
(25 - 16)/4 = x  
x = 9/4  
x = 2.25 m........


I think it is ur answer