Question

a particle moves with constant speed 20m/s in a circular path of radius 100m the magnitude of change in velocity when particle reaches diametrically opposite point is​

Answer 1

Given:

A particle moves on a circular path of radius 100m with a constant speed of 20 m/s.

To find:

Change in velocity when particle reaches the diametrically opposite point?

Calculation:

• First of all, velocity is a vector quantity. So, apart from magnitude, we also need to consider the direction of the quantity.

So, at the diametrically opposite point, the direction of velocity will be opposite to the direction of velocity at the initial point.

$\Delta v = v_{2} - v_{1}$

$\implies \Delta v = 20 - ( - 20)$

$\implies \Delta v = 20 + 20$

$\implies \Delta v = 40 \: m {s}^{ - 1}$

So, change in velocity is 40 m/s.