Question

A particle moves with constant speed v along a regular
hexagon ABCDEF in the same order. Then the magnitude
of the average velocity for its motion from A to

(1) F is v/5
(2) D is v/3
(3) C is v√3/4
(4) B is v/2
​

Answer 1

Answer:

Let side length be 'a' From A to B

For A to B:

V

=

time

displacement

⇒

V

a

a

=V

For A to C:

V

=

V

2a

2aSin60

=

2

3

V

For A to D:

V

=

V

3a

2a

=

3

2

V

For A to F:

V

=

V

5a

a

=

5

1

V