a particle moves with costant acceleration of 6m/s2 due to west has an initial velocity of 12m/s due to east. find distance travelled in 7 sec
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acceleration is towards east
so a= -6m/s²
u (initial velocity) = 12 m/s
t = 7 sec
s (distance) =?
s = ut+1/2at²
s = 12 x 7 + 1/2 x -6 x 7²
s = -63m (towards west)
therefore, particle has travelled 63 m east
so a= -6m/s²
u (initial velocity) = 12 m/s
t = 7 sec
s (distance) =?
s = ut+1/2at²
s = 12 x 7 + 1/2 x -6 x 7²
s = -63m (towards west)
therefore, particle has travelled 63 m east
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