Question

A particle moves with r=3cos4t+3(1-4sin3t). find distance at t=0.5sec

Answer 1

A particle moves with r = 3cos4t + 3( 1- 4sin3t) . Here r is distance travelled in time " t "

Now, r = 3 ( cos 4(0.5) ) + 3 ( 1 - 4sin1.5 )

r = 3 cos2 + 3 - 12 sin5

r = 3 ( 0.99) + 3 - 12 ( 0.08)

r = 2.97 + 3 - 0.96

r = 5.97 - 0.96

r = 5.01 m ( Approximately)