Question

A particle moves with the velocity →v=(5^i+2^j−^k)ms−1v→=(5i^+2j^−k^)ms−1 under the influence of a constant force,→F=(2^i+5^j−10^k)NF→=(2i^+5j^−10k^)N. The instantaneous power applied is​

Answer 1

Answer:

4 joule 29 km

Step-by-step explanation:

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