Question

A particle moves with uniform acceleration and the distance traveled in t th second is s=3+2t.Find the initial velocity of the particle. ​

Answer 1

$\boxed{\sf \pink{Answer}}$

initial velocity = 2 m/s

$\boxed{\sf \pink{Explanation}}$

Given:

• S = 3+2t

where, 'S' is displacement and 't'is time

To Find:

initial velocity (u)

Solution:

S = 3 + 2t

Differentiating on both sides with respect to time (t)

$\mathsf{\dfrac{dS}{dt} =\dfrac{d(3+2t)}{dt} }$

$\mathsf{v = 2 }$

Now,

Differentiating on both sides with respect to time (t)

$\mathsf{\dfrac{dv}{dt} =\dfrac{d(2)}{dt} }$

$\mathsf{a = 0 }$

$\boxed{\bold \green{{v}^{2}-{u}^{2} = 2aS}}$

$\mathsf {{2}^{2}-{u}^{2} = 2(0)S}$

$\mathsf {{2}^{2}-{u}^{2} = 0}$

$\mathsf {{2}^{2} = {u}^{2} }$

$\mathsf {u = 2}$

Initial velocity = 2m/s

Note:

When a = 0 . then,

Initial velocity = Final Velocity