Question

a particle moves with uniform acceleration covers 25m in 5th second and 35m in 7th second of its journey then the distance travelled in its 3rd second will be

Answer 1

given that it is in uniform acceleration so we can take the given value as velocity

v = 25m/5s => 5m/s

v = 35m/7s => 5m/s

so there is no change in velocity

v = x/t                                                              x is distance

5(3) = x                          

x = 15m