Question

A particle moves with velocity (5i+3j+6k)m/s under the influence of a constant force (5i+5j+10k).The instantaneous power applied to the particle is

Answer 1

power=F . V
25+15+60
=100 Watt

Answer 2

Answer:

Power, P = 100 watts

Explanation:

It is given that,

Velocity of the particle, $v=(5i+3j+6k)\ m/s$

Magnitude of velocity, $|v|=\sqrt{5^2+3^2+6^2}=8.36\ m/s$

Force acting on the particle, $F=5i+5j+10k$

Magnitude of force acting on the particle, $|F|=\sqrt{5^2+5^2+10^2}=12.24\ N$

The power applied to the particle is given by :

$P=\dfrac{W}{t}$

W = F.d

$P=\dfrac{F.d}{t}$

$\dfrac{d}{t}=v$

$P=F.v$

$P=(5i+3j+6k)\times (5i+5j+10k)$

$P=25+15+60=100\ watts$

P = 100 watts

So, the instantaneous power applied to the particle is 100 watts. Hence, this is the required solution.