A particle moves with velocity function v(t) = -t2 + 5t - 3, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds
Answers
Answered by
7
given V( t )= -t² +5t -3
differentiate both sides with respect to t
d( v) /dt =-2t + 5v
or d (v)/dt. when t =3 =-2(3) +5
acceleration. = -1
bcoz rate or change of velocity gives acceleration
differentiate both sides with respect to t
d( v) /dt =-2t + 5v
or d (v)/dt. when t =3 =-2(3) +5
acceleration. = -1
bcoz rate or change of velocity gives acceleration
Answered by
3
The acceleration of the particle at time t = 3 seconds is .
Explanation:
A particle moves with velocity function is given by :
Where
v is in feet per second and t measured in seconds
The acceleration of an object is given by :
At t = 3 second
So, the acceleration of the particle at time t = 3 seconds is .
Learn more,
Velocity and acceleration
https://brainly.in/question/10876646
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