A particle moves with velocity v=5t find acceleration at t =3 sec
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a=dv/dt,
a=5m/s^2 at any time ,because it is constant.
a=5m/s^2 at any time ,because it is constant.
wbhat:
acceleration = rate of change of velocity. a = dy / dt. a = d(5t)/ dt = 5 d(t) /dt = 5(1) = 5 ms-² = here acceleration is not a function of time , so itz finite constant acceleration..
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initial velocity=5×0 (t=o)=0m/s
final velocity=5×3 (t=3) =15m/s
acceleration= v1-v2/t1-t2
=15-0/3-0
=15/3
=5m/s^2
final velocity=5×3 (t=3) =15m/s
acceleration= v1-v2/t1-t2
=15-0/3-0
=15/3
=5m/s^2
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