Question

a particle movies along x axis whose position varies from x= t^2-4t+8. find the total distance travelled in first four seconds​

Answer 1

To find:-

Total distance in 1st 4second= ?

Solution:-

Given,

position (x) = t²-4t+8

So, in 1st 4 second

distance (x) = 4²-4×4+8

= 16-16+8 = 8 unit .

Hope it's helpful to you .