Question

A particle moving along a circular path has equal magnitudes of linear and angular acceleration. The diameter of the path is (in meter)

Answer 1

We know,
$a = \alpha r$


$\alpha = angular \: accelertion \\ a = linear \: acceleration \\ r = \: radius \: of \: curvature \: of \: the \: path$
Since, in this case both Angular acceleration and Linear acceleration are of equal magnitude, so,
r=1 unit. (where the unit can be either of metre or centimetre)