A particle moving along a circular track of radius 1m with uniform speed. Find the ratio of distance covered and displacement in half revolution
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Answered by
6
in ½ revolution it complete ½ circle
hence distance=πr. = π*1
=π
displacement = 2r=2*1=2
hence (distance/displacement)=π/2
Hope this will help you..
hence distance=πr. = π*1
=π
displacement = 2r=2*1=2
hence (distance/displacement)=π/2
Hope this will help you..
Answered by
5
distance would be 2pier (where are is 1)
distance would be 2*22/7*1
that is 44/7or if we take pie as 3.14 then answer would be 6.28
displacement would be zeros as it is change from intial poistion to final that is zero as it comes to intial point
ther ratio will be 3.14:0
distance would be 2*22/7*1
that is 44/7or if we take pie as 3.14 then answer would be 6.28
displacement would be zeros as it is change from intial poistion to final that is zero as it comes to intial point
ther ratio will be 3.14:0
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