A particle moving along a straight line has a velocity v m/s , when ot cleared a distance of xm. These two are connected by the relation v=(49+x)^1/2. When its velocity is 1m/s , its acceleration is?
Answers
Answered by
10
given
v=root49+x
therefore acceleration a=dv/dt
a=(root49+x)*dx/dt
=49+xm/s square
v=root49+x
therefore acceleration a=dv/dt
a=(root49+x)*dx/dt
=49+xm/s square
Answered by
3
follow these steps:
1)equation of v is given.
2)to derive the equation of acceleration, differentiate the equation of v with time.
3)the final equation will give the relationship between acceleration and velocity.
4)put the value of velocity in the derived equation and hence value of acceleration can be found.
Similar questions