A particle moving along a straight line has an acceleration of (3t-4). Find the displacement of the particle from the origin when time is 3 seconds.
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given a = 3t-4
v = integration (a*dt) = 3/2*t^2-4t
x = integration v*dt = 3/6t^3 - 2t^2 (put t=3)
x = 27/2 - 18 = 13.5-18 = -4.5
v = integration (a*dt) = 3/2*t^2-4t
x = integration v*dt = 3/6t^3 - 2t^2 (put t=3)
x = 27/2 - 18 = 13.5-18 = -4.5
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