Question

A particle moving along a straight line with a velocity of 2m/s is accelerated uniformly in the same direction.(i) If its velocity becomes 20m/s at the end of 9s, find the accelaration.(ii) Calculate its velocity when the displacement is 35m.​

Answer 1

Answer:

so initial velocity is 2 ms^-1

and final velocity is at the end of 9 sec is 20 ms^-1

since it is uniform acceleration it will be constant throughout the journey

v=u+at

20 = 2 + a×9

a = 2ms^-2

acceleration is 2ms^-2

to find velocity at 35m use v^2 - u^2 = 2as

s = displacement

v = final velocity at 35m

u = initial velocity

a = acceleration

put the values

v^2 = u^2 + 2as

v^2 = 2^2 + 2×2×35

v^2 = 144

v = sqrt 144

v = 12 ms^-1

hence the velocity is 12ms^-1

here aqrt means sqyare root

hop it helps !!