Question

a particle moving along a straight line with constant acceleration of -2m/s^2 has a velocity of 6m/s at t=0 sec. find the ratio of distance and displacement at t=0 sec

Answer 1

Answer:

Hope it will help you...

Answer 2

Answer:

13:5

Explanation:

v = u+ at

v = 6-2t v=0

so, 6- 2t =0 t= 3 sec

Distance = A1 +A2 =1/2(6.3) +1/2(2.4) =13

Displacement = A1-A2 =1/2(6.3)-1/2(2.4) =5

Therefore the ratio =13:5