a particle moving along a straight line with constant acceleration of -2m/s^2 has a velocity of 6m/s at t=0 sec. find the ratio of distance and displacement at t=0 sec
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13:5
Explanation:
v = u+ at
v = 6-2t v=0
so, 6- 2t =0 t= 3 sec
Distance = A1 +A2 =1/2(6.3) +1/2(2.4) =13
Displacement = A1-A2 =1/2(6.3)-1/2(2.4) =5
Therefore the ratio =13:5
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