Question

A particle moving along a straight line with constant acceleration is having initial and final velocity an
5 m/s and 15 m/s respectively in a time interval of 5 s. Find the distance travelled by the particle and the
acceleration of the particle. If the particle continues with same acceleration, find the distance covered
by the particle in the 8th second of its motion. (Direction of motion remains same)

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Answer 1

Answer:

2m

Explanation:

v2-v1=15-10=10

t=5

d=v/T=10/5=2m

Answer 2

Hope this helps. Please comment in case of any doubt. Thanks