Question

A particle moving along a straight line with uniform acceleration covers distance ab=8m and bc=18m in one second each, the speed of the particle at point b is

Answer 1

Answer:

13m/s

Explanation:

8+18/2

=26/2

=13m/s

Answer 2

Therefore the speed of the particle at point 'B' is 13 m/s.

Given:

The acceleration of the particle between AB = 8 m

The acceleration of the particle between BC = 18 m

Time taken to travel AB = 1 sec

Time taken to travel BC = 1 sec

To Find:

The speed of the particle at point B.

Solution:

The given question can be solved as shown below.

Given that,

The acceleration of the particle between AB a₁ = 8 m

The acceleration of the particle between BC a₂ = 18 m

Time taken to travel AB t₁ = 1 sec

Time taken to travel BC t₂ = 1 sec

Velocity of the particle between AB = a₁ × t₁ = 8 × 1 = 8 m/s

Velocity of the particle between BC = a₂ × t₂ = 18 × 1 = 18 m/s

The average of both the velocities gives the velocity at point 'B',

⇒ V = ( 8 + 18 ) / 2 = 26/2 = 13 m/s

Therefore the speed of the particle at point 'B' is 13 m/s.

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