Question

a particle moving along a straight road with constant accerlation of -4m/s² passes through a point A on the line with velocity 20 m/s at some moment the distance travelled by the particle in 10 s i​

Answer 1

• initial velocity=u=20m/s
• Acceleration=-4m/s^2=a
• Time=t=10s
• Distance=s=?

Using second equation of kinematics

$\boxed{\sf s=ut+\dfrac{1}{2}at^2}$

$\\ \sf\longmapsto s=20(10)+\dfrac{1}{2}\times (-4)(10)^2$

$\\ \sf\longmapsto s=200+(-1)(100)$

$\\ \sf\longmapsto s=200-100$

$\\ \sf\longmapsto s=100m/s^2$

Answer 2

Answer:

0 m

Explanation:

Just use Newton's third equation of motion