A particle moving along circular path of radius 1m completes 2(1/4)th revolution. Then displacement and distance of the particle are ( in metre )
Answers
Answer:
Distance=π∗R=π displacement=2∗R=1∗2=2
therefore the ratio the distance covered and the displacement in half revolutionr=
2
π
Answer:
3.14 meters and 2 meters.
Explanation:
Given:
The radius of the path ,r = 1 meter.
Number of revolutions= 2( 1/4)th = 1/2
It is moving in a circular path.
Distance :
The distance covered by the particle along the circular path will be equal to the circumference of a circle whose formula is 2πr.
According to the question=
The distance covered = of 2πr
= πr.
= π × 1 .
= 3.14 meters.
Displacement :
The displacement of the particle is the shortest distance covered by it.
⇒ 2r
Displacement = 2 × 1
= 2 meters
∴ The distance and displacement of a particle moving in a circular path is 3.14 meters and 2 meters respectively.
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