Question

A particle moving along circular path of
radius 1m completes 2(1/4)th revolution.
Then displacement and distance of the
particle are (in metre)
​

Answer 1

Explanation:

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Answer 2

Displacement at end of two revolutions is equal to zero. Now after next 1/4th revolution,

Using Pythagoras therorem

Displacement (see from fig) =

\sqrt{ {1}^{2} + {1}^{2} } = \sqrt{1 + 1} = \sqrt{2}

1

2

+1

2

=

1+1

=

2

Distance = 2.25 × 2πr = 2.25 × 2π×1

= 4.5π = 9π/2