A particle moving along the x axis has a position given by x- (-9+241-21) m, where t is measured in s. How far is the particle from the origin (x-0) when the particle is not moving?
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The position of a particle moving along x-axis is given by
x=(−2t3+3t2+5)m
Velocity, v=dtdx=0
−6t2+6t=0. . . . . . .(1)
6t(−t+1)=0
−t+1=0
t=1sec
Acceleration, a=dtdv
a=−12t+6
a∣t=1sec=−12×1+6
a∣t=1sec=−6m/s2
Explanation:
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