A PARTICLE MOVING ALONG TNE CIRCUMFERENCE OF A CIRCLE OF RADIUS R HAS ITS RADIUS VECTOR TURNED THROUGH 90° WHAT IS THE DISPLACEMENT
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Answer:
√(2r²)
Explanation:
at 90 degree it becomes a right angled triangle then through pythagoras theorem because the displacement is the hypotenuse of the triangle
(Displacment)²=r²+r²
therefore displacement is √(r²+r²)
which is √(2r²)
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