A particle moving in a circular path of radius 5 m has a tangential acceleration of 5m
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GIVEN DATA:-
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RADIUS=5m
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TANGENTIAL ACCELERATION =5m
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REQUIRED :-
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V=?
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FORMULA:-
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a=v^2÷r
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v^2=a×r
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v^2=5×5
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v^2=25
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square root v^2=square root 25
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v=5
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♡♤♡ INSHALLAH IT WILL HELP U♤♡♤
●●●●●●●●●●●●●●●●●●●●
GIVEN DATA:-
▪▪▪▪▪▪▪▪▪
RADIUS=5m
▪▪▪▪▪▪▪▪▪
TANGENTIAL ACCELERATION =5m
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪
●●●●●●●●●●●●●●●●●●●●●●
REQUIRED :-
▪▪▪▪▪▪▪▪▪▪
V=?
▪▪▪▪
FORMULA:-
▪▪▪▪▪▪▪▪
a=v^2÷r
▪▪▪▪▪
v^2=a×r
▪▪▪▪▪
v^2=5×5
▪▪▪▪▪▪▪
v^2=25
▪▪▪▪▪▪
square root v^2=square root 25
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪
v=5
▪▪▪▪
♡♤♡ INSHALLAH IT WILL HELP U♤♡♤
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