Physics, asked by rohitre1, 1 year ago

A particle moving in a straight line covers half of a distance with Speed 3 metre per second the other half of a distance is covered in 2 equal time intervals at speed of 4.5 M second and 7.5 seconds respectively the average speed of particle during this
motion

Answers

Answered by Brainlyhelper38
197

Step - by - Step Explanation :

  • Speed = distance / time

  • By using this formula you can get answer quickly .

  • we simply added the distance and time and distance per unit time is called ' Average speed ' .
Attachments:
Answered by CarliReifsteck
304

Answer:

The average speed of particle during this  motion is 4 m/s.

Explanation:

Given that,

First half of a distance is covered with speed = 3 m/s

The other half of a distance is covered in 2 equal time intervals at speed of 4.5 M second and 7.5 seconds respectively

Let the total distance covered be 2 x.

Let t be the time taken the first half of the distance.

t = \dfrac{x}{3}

Let the other half of a distance be covered in two equal intervals of time.

x=4.5t'+7.5t'

x=12t'

t'=\dfrac{x}{12}

The total time is

t''=t+2t'

t''=\dfrac{x}{3}+2\times\dfrac{x}{12}

t''=\dfrac{x}{3}+\dfrac{x}{6}

The average speed is equal to the total distance divided by the total time.

v_{avg}=\dfrac{2x}{\dfrac{x}{3}+\dfrac{x}{6}}

v_{avg}=4 m/s

Hence, The average speed of particle during this  motion is 4 m/s.

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