A particle moving in a straight line covers half of the distance with a speed of 3m/s.The other half is covered into equal time intervals with a speed of 4.5m/s and 7.5m/s respectively. The average speed of the particle during its motion is
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Ans. Avarage speed= 4.5 mtrs/sec
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Answer:
4 m/s
Explanation:
let the distance of the first half = s/2
and the distance of the second half = s/2
the time of the first half = s/6
the time of the second half = s/2 ÷ (7.5 + 4.5)/2 = s/12
total time = s/6 + s/12 = s/4
average speed = total distance ÷ total time
Vav = s ÷ s/4 = 4 m/s
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